hi, I m using H7A3 nucleo, manage to get SPI polling working, enclose code below, when i try in implement Interrupt and DMA , the code compile successfully with no error, but SPI output no signal, SPI slave device is a TI ADC...I have set SPi global...
Hii st-term Can you please tell what is issue in this code it is going in Error Handler HAL_StatusTypeDef HAL_CAN_AddTxMessage(CAN_HandleTypeDef *hcan, const CAN_TxHeaderTypeDef *pHeader, const uint8_t aData[], uint32_t *pTxMailbox) { uint32...
Hi, I am using 3 DMA channels of DMA1 on a STM32G4* to transfer data from the 3 ADCs to mem. At a certain point I want to make sure that all transfers are done and enter a while loop: uint32_t timeoutCnt = 0; while(!LL_DMA_IsActiveFlag_TC1(DMA1) || ...
Can M4 write to part of Bank 1 when M7 code is running from Bank 1? Idea is to define apartition at the end of Bank 1 and M4 write to it while M7 reads from it. I know thisneeds some tweaking of the dts to assign both Bank 1 and Bank 2 to M4 as below...
I am using STM32F446RE microcontroller and using MATLAB to develop the logic. Upon launching StmCubeMx, I have kept the clock frequency as 90MHz and 10% duty cycle for TIM1, TIM2, TIM3. So, it gives same output frequency of the pulses (PWM_Output.png...
I have both STM32F1038T6 and STM32F401CC. I have been trying to get a code to run from ram for days now. Im using arduino ide with stm32duino. i first create a buffer in ram with malloc then copy the code to the buffer using memcpy. The code is in ...
Hi, I am having problem with string copy strncpy(). I am getting error message "Cannot access memory at address 0x31203a6e" static char *DataBuffer[30] = {0}; for(char *str =strtok((char*)recdata, "\n\n"); str; str = strtok(NULL, "\n\n")) { strncp...
Dear Sir,I use NUCLEO-L476 , Once I connect it to usba new window pop up like with the Caption NODE_L476RG .Erasing the CPU still the window pop up.What should I do to make this board to act as plain PCB
Hi,Why there are no QFN packages for STM32U59 series? Will it be added in the future?Thanks.
