STM32 MCUs Embedded software

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STM32F4 USB HOST HID problem

Posted on August 04, 2017 at 16:47I'm rather new in USB domain and I'm using ST std periph library and STM32_USB-Host-Device_Lib_V2.1.0 (and V2.2.0) on STM32F4 (my own board and STM32F407 Discovery). I've tested MSC host and it works fine but about ...

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CMSIS - pros and cons

Posted on August 04, 2017 at 10:40Hi,We're entering a new project with STM32F7676 and thinking about which RTOS to use. Our [initial] understanding is that CMSIS is a set of standardized APIs to peripherals, driver and to an actual RTOS implementati...

RTOS config from CubeMX not working

Posted on June 26, 2017 at 10:17Hi, I am new to putting together my own projects and have followed this http://www.carminenoviello.com/2015/06/22/running-freertos-stm32nucleo-free-gcceclipse-toolchain/&sharpcomment-78392 great write up, adapting the...

USB FS CDC

Posted on August 03, 2017 at 13:53I try to make a USB CDC HOST FS with an Nucleo STM32F746ZG but,I made the project with CubeMx and when i plug my device the enumeration work, i can see it with a beagle usb but i don't reach the HOST_USER_CLASS_ACTI...

Resolved! Getting an interrupt at specific encoder value

Posted on July 31, 2017 at 14:41Beginner working with STM32L452:I have TIM2 set up as encoder-based timer. Works perfect.Now I want an interrupt whenever the TIM2 reaches a certain value (position).I tried to enable timer interrupt through HAL_TIM_E...

Krix N by Associate II
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Resolved! STM32F756 USB and WFI

Posted on July 27, 2017 at 09:55I have a problem with STM32F756 USB CDC (HS with FS PHY) device and core sleeping. I isolated all other code and left only the USB driver and main loop calling WFI instruction. If there is no call to WFI, USB is worki...

Any reason not to use CAN identifier as node ID?

Posted on July 31, 2017 at 02:17Preamble for the uninitiated:CAN identifiers are usually associated/related with/to the content of the message rather than as an identification mechanism for a specific participant on the bus.The question therefore:In...

connect by Associate II
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