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Inquiry on STM Controllers with Sinusoidal PWM Capability for Dual H-Bridge Applications

sonaliz
Associate

Hello,

Can you please check if STM manufactures controllers with Sinusoidal PWM, our requirement is to drive 2 H-bridge full drivers, so if they are available please let me know.

 

Thanks,

Sonali

1 ACCEPTED SOLUTION

Accepted Solutions
SofLit
ST Employee

Hello,

There is no feature called "Sinusoidal PWM" on STM32 but you can generate sinusoidal with a timer PWM output.

You can refer to this article:

https://community.st.com/t5/stm32-mcus/how-to-generate-a-sine-wave-using-pwm-and-rc-filter-with-the/ta-p/49415

Watch also this video: https://www.youtube.com/watch?v=4omSQHY0rDw

You can also use DAC to generate sine wave:

See these threads: https://community.st.com/t5/stm32-mcus-products/how-to-generate-a-sine-wave-using-dac-with-stm32f410rb-using/td-p/694638

https://community.st.com/t5/stm32-mcus-products/how-to-generate-a-sine-wave-using-dac-and-dma-with-the/td-p/687189

Hope it does answers your question.

To give better visibility on the answered topics, please click on "Accept as Solution" on the reply which solved your issue or answered your question.

View solution in original post

1 REPLY 1
SofLit
ST Employee

Hello,

There is no feature called "Sinusoidal PWM" on STM32 but you can generate sinusoidal with a timer PWM output.

You can refer to this article:

https://community.st.com/t5/stm32-mcus/how-to-generate-a-sine-wave-using-pwm-and-rc-filter-with-the/ta-p/49415

Watch also this video: https://www.youtube.com/watch?v=4omSQHY0rDw

You can also use DAC to generate sine wave:

See these threads: https://community.st.com/t5/stm32-mcus-products/how-to-generate-a-sine-wave-using-dac-with-stm32f410rb-using/td-p/694638

https://community.st.com/t5/stm32-mcus-products/how-to-generate-a-sine-wave-using-dac-and-dma-with-the/td-p/687189

Hope it does answers your question.

To give better visibility on the answered topics, please click on "Accept as Solution" on the reply which solved your issue or answered your question.