STM32U575/585, how to enter ROM bootloader to flash SW at very first time.

[JR.3]

First I was reading:

Reference manual

STM32U575/585 Arm®-based 32-bit MCUs

4 Boot modes

ST programmed

default value

NSBOOTADD0[24:0]

Flash: 0x0800 0000

NSBOOTADD1[24:0]

Bootloader:

0x0BF9 0000

Then:

AN2606

Application note

STM32 microcontroller system memory boot mode

The STM32U575xx/85xx bootloader is activated by applying pattern12

TZen = 0, Boot0(pin) = 0, nSWBoot0(bit) = 1 and NSBOOTADD0 [24:0] = 0x017F200

TZen = 0, Boot0(pin) = 1, nSWBoot0(bit) = 1 and NSBOOTADD1 [24:0] = 0x017F200

TZen = 0, nBoot0(bit) = 0, nSWBoot0(bit) = 0 and NSBOOTADD1 [24:0] = 0x017F200

TZen = 0, nBoot0(bit) = 1, nSWBoot0(bit) = 0 and NSBOOTADD0 [24:0] = 0x017F200

But what are default values for nBoot0 and nSWBoot0 ?

I'am trying to understand how to enter ROM bootloader at very first boot.

[Piranha]

Most likely it was forgotten to update that value after the actual value to use was decided, when the chip was released. As explained above, the default (factory) value should be put in the reference manual as it is done for other series.

@Imen DAHMEN​, maybe you can fix/report this...

[Imen.D]

Hello @Piranha​ ,

Thank you for flagging this for me!

I raised this request internally for fix.

Thanks

Imen