Is it not advisable to load both registers using ldw ?Like this: uint16_t tim3_last = *(const uint16_t *)&(TIM3->CNTRH); which produces: ldw x, 0x5328
ldw (0x07, sp), x Would MSB or LSB be loaded first by the hardware?
Actually, D2 and E2 should simply be not referenced on the drawing. 0.55 should be 0.5, per `e` dimension.So now 3x0.5+0.3=1.8mm It should be numerically written 1.80 and then everything starts to make sense. Here is an overlay: And here is correct...
It happens when two monitors are connected and a certain configuration. I have 3000x2000 laptop monitor with 200% scale and a second 1920x1080 with 100% scale. The second monitor is set as main. Setting laptop as main fixes the problem temporarily.I...
