using printf to display a buffer in hex format

[lowpowermcu]

Posted on August 18, 2010 at 13:25

using printf to display a buffer in hex format

[luca239955_stm1_st]

Posted on May 17, 2011 at 15:10 I think replacing'' %04X'' with ''%2x'' should work (haven't tried though) Luca

[lowpowermcu]

Posted on May 17, 2011 at 15:10

Hi ubiali,

I have tried ''%2x'' and ''%1X'' and I got 800 for 0x08 and 1f00 for 0x1f. What could be the solution ? Is related to stdlib ? Thanks for the help ! Thanks & Regards, MCU Lüfter

[luca239955_stm1_st]

Posted on May 17, 2011 at 15:10

Hi,

I just tried unsigned int buffer[] = {0x08, 0x1f}; void main(void) { printf(''%02x %02x'', buffer[0], buffer[1]); } and it prints 08 1f with the Cosmic stm8 compiler. Regards, Luca

[luca239955_stm1_st]

Posted on May 17, 2011 at 15:10 cast to int when calling printf: printf(''%02x %02x'', (int)buffer[0], (int)buffer[1]); Regards, Luca

[lowpowermcu]

Posted on May 17, 2011 at 15:10

Hi ubiali,

Thanks for your test but my buffer is unit8_t type and when I print I am getting ''800'' and ''1f00''. I think that ''%02x'' works for unsigned int (16 bits) and not for uint8_t (8 bits). What could you suggest ? By curiosity, I have tried another compiler and I have found that it prints with %2.2 (and I am not sure that this is what should be). I am really thankful. Regards, MCU Lüfter