Posted on May 02, 2018 at 12:34I know this is an old problem but I really cannot figure out.
My intention is to use timer 15 as a trigger source with setting equal to 1kHz. Then by enabling ADC interrupt using EOC flag I think I could have an ADC interrupt of 1kHz used to convert 5 channels (they are not sampling at the same rate, so I want to use this ADC interrupt to set another time period.....)
I have the below source code: I could not enter the interrupt routine even one time.
void initADC(void)
{
ADC1->CFGR1 =
_VAL2FLD(ADC_CFGR1_DISCEN, 1) | // discontinuous mode
_VAL2FLD(ADC_CFGR1_AUTOFF, 0) |
_VAL2FLD(ADC_CFGR1_WAIT, 0) |
_VAL2FLD(ADC_CFGR1_CONT, 0) |
_VAL2FLD(ADC_CFGR1_OVRMOD, 0) |
_VAL2FLD(ADC_CFGR1_EXTEN, 1) |
_VAL2FLD(ADC_CFGR1_EXTSEL, 4) |
_VAL2FLD(ADC_CFGR1_ALIGN, 0) | // data right aligned
_VAL2FLD(ADC_CFGR1_RES, 0) | // 12 bit resolution
_VAL2FLD(ADC_CFGR1_SCANDIR, 0) | // upward scan
_VAL2FLD(ADC_CFGR1_DMACFG, 1) | // DMA circular mode
_VAL2FLD(ADC_CFGR1_DMAEN, 0); // DMA disabled
ADC1->CFGR2 |= ADC_CFGR2_CKMODE_0;
// sampling time set to 28.5 ADC clock cycles:
ADC1->SMPR = _VAL2FLD(ADC_SMPR_SMP, 3);
//I have 5 channels but just test one channel first
ADC1->CHSELR = ADC_CHSELR_CHSEL1; //| //PA1
//ADC_CHSELR_CHSEL8 | //PB0
//ADC_CHSELR_CHSEL9; //PB1
ADC1->IER |= ADC_IER_EOCIE;
cfp_SetBit(&ADC1->ISR, ADC_ISR_ADRDY); // clear ready flag
cfp_SetBit(&ADC1->CR, ADC_CR_ADEN);
while (!cfp_IsBitSet(ADC1->ISR, ADC_ISR_ADRDY)) {
;
}
cpu_EnableInterrupt(ADC1_COMP_IRQn);
//init timer 15
TIM15->PSC = 47; //48MHz / 48
TIM15->ARR = 999; //set to 1kHz
TIM15->CCR2 |= TIM_CR2_MMS_1;
TIM15->EGR |= TIM_EGR_UG;
TIM15->CR1 |= TIM_CR1_CEN;
cfp_SetBit(&ADC1->ISR, ADC_ISR_EOS); // clear end of sequence flag
cfp_SetBit(&ADC1->CR, ADC_CR_ADSTART);
}
void ADC1_COMP_IRQHandler(void)
{
if( (ADC1->ISR & ADC_ISR_EOC) )
{
ADC1->ISR &= ~(ADC_ISR_EOC);
digio_ToggleOutputValue(GPIOB, 14);
}
}
Thank you in advance for any help...........
