2022-03-02 09:57 AM
We are using the STM32H753 and cannot enter the bootloader using pattern 8.
AN2606 states that when BOOT0 is low and the option byte BOOT_ADD0 is 0x0040, then the bootloader is activated.
Does this work for the STM32H753?
Pattern 8
Option byte set to 0x0040 in STM32CubeProgrammer
Thanks for your help!
Solved! Go to Solution.
2022-03-02 10:23 AM
For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.
Pattern 10:
2022-03-02 10:23 AM
For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.
Pattern 10:
2022-03-02 10:40 AM
Thank you again TDK! I learned twice today.
2022-03-02 10:44 AM
I will try this today, but I think I tried this already and it didn't work. I will come back.
2022-03-02 12:05 PM
Ok I tried this again. With my setup, I seem to have trouble entering into the bootloader on a power cycle. If I reset the processor by pulling NRST low and releasing I can communicate with the bootloader.
Thanks TDK for your help.