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Problem entering the bootloader using the STM32H753 and pattern 8

TSosi.1
Associate III

We are using the STM32H753 and cannot enter the bootloader using pattern 8.

AN2606 states that when BOOT0 is low and the option byte BOOT_ADD0 is 0x0040, then the bootloader is activated.

Does this work for the STM32H753?

Pattern 8

0693W00000KbAw4QAF.pngOption byte set to 0x0040 in STM32CubeProgrammer

0693W00000KbAxgQAF.png 

Thanks for your help!

1 ACCEPTED SOLUTION

Accepted Solutions
TDK
Guru

For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.

0693W00000KbB72QAF.png 

Pattern 10:

0693W00000KbB7CQAV.png

If you feel a post has answered your question, please click "Accept as Solution".

View solution in original post

4 REPLIES 4
TDK
Guru

For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.

0693W00000KbB72QAF.png 

Pattern 10:

0693W00000KbB7CQAV.png

If you feel a post has answered your question, please click "Accept as Solution".
TSosi.1
Associate III

Thank you again TDK! I learned twice today.

TSosi.1
Associate III

I will try this today, but I think I tried this already and it didn't work. I will come back.

TSosi.1
Associate III

Ok I tried this again. With my setup, I seem to have trouble entering into the bootloader on a power cycle. If I reset the processor by pulling NRST low and releasing I can communicate with the bootloader.

Thanks TDK for your help.