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STM32F4 Discovery : Why U4A and U4B in schematics when the MCU is marked as U4 on the PCB?

skrowten_hermit
Associate II

I'm just learning to read and use schematics and I found that while physically the MCU (STM32F407VG on my STM32F4 Discovery board) is marked U4 as the part number on the PCB, the schematic (Section "STM32Fx" of "MB997-F407VGT6-D01_Schematic.pdf") shows 2 separate blocks U4A and U4B. I understand that U4A is the ports with the pins for I/O or peripheral interfacing. I have the following questions:

  1. What exactly is U4B?
  2. Why is U4 split this way?

It would be great if I get answers to the above questions. I have attached a screen grab of the same below.0693W00000FCwrqQAD.png

1 ACCEPTED SOLUTION

Accepted Solutions
Peter BENSCH
ST Employee
  1. As you have already mentioned, the U4A block contains the digital in-/outputs. U4B is the part of U4 that has to do with power supply, so no digital in-/outputs.
  2. It has been splitted to make it clearer.

Regards

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.

View solution in original post

1 REPLY 1
Peter BENSCH
ST Employee
  1. As you have already mentioned, the U4A block contains the digital in-/outputs. U4B is the part of U4 that has to do with power supply, so no digital in-/outputs.
  2. It has been splitted to make it clearer.

Regards

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.