cancel
Showing results for 
Search instead for 
Did you mean: 

Hello, we have bought the NPN transistor 2N5154RSRHRG. At your datasheet, page 1, product summary, you mention that for this part the emitter is on pin 1. But on table 7, page 10, you mention that the emitter is on pin2. Could you please clarify that?

PKala.3
Associate II
 
1 ACCEPTED SOLUTION

Accepted Solutions
Peter BENSCH
ST Employee

Oh, it looks like there's a typo in the data sheet: page 1, Product Summary, mentioned in the last two lines:

  • 2N5154RSRHRx, ESCC, 5203/010, SMD.5, 100 krad, LDR, emitter on pin 1
  • 2N5154SRHRx, ESCC, 5203/010, SMD.5, Emitter on pin 2

should be read as:

  • 2N5154RSRHRx, ESCC, 5203/010, SMD.5, 100 krad, LDR, emitter on pin 2
  • 2N5154SRHRx, ESCC, 5203/010, SMD.5, Emitter on pin 2

But table 7, ordering information correctly lists the options of the pin-out.

Yes, you can use your diagram with the red marked pin numbers for this part number.

Regards

/Peter

P.S.: It is permissible, but it is still not a good idea to reply by email to messages from the community, because the reply email usually sends all private data (telephone numbers, addresses, etc). This is then visible to everyone in this community, which is open to the public worldwide. To ensure data protection, you should therefore not reply by email, but via the community's web interface.

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.

View solution in original post

4 REPLIES 4
Peter BENSCH
ST Employee

Welcome, @PKala.3​, to the community!

On pages 1 and 9 of the data sheet you will find the note "base and emitter are inverted for 2N5154RSRHRx and 2N5154SRHRx series".

The word inverted is a bit unfortunate, because it actually refers to a logical function, but here it means the exchanged function of base and emitter.

Does it answer your question?

Regards

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.

Dear Mr. Bensch,

Thank you for your reply.

Could you please confirm that on the P/N: 2N5154RSRHRG, the emitter is on pin2 and not on pin1 (as it is mentioned on the table of Product Summary (column ‘Remarks’))?

Can we use the following diagram for this part number?0693W00000QNOKjQAP.png 

Freundliche Grüsse / Kind regards

Panagiotis Kalaitzidis

PKala.3
Associate II

Dear Mr. Bensch, could you please confirm the above?

Best regards,

Panagiotis Kalaitzidis

Peter BENSCH
ST Employee

Oh, it looks like there's a typo in the data sheet: page 1, Product Summary, mentioned in the last two lines:

  • 2N5154RSRHRx, ESCC, 5203/010, SMD.5, 100 krad, LDR, emitter on pin 1
  • 2N5154SRHRx, ESCC, 5203/010, SMD.5, Emitter on pin 2

should be read as:

  • 2N5154RSRHRx, ESCC, 5203/010, SMD.5, 100 krad, LDR, emitter on pin 2
  • 2N5154SRHRx, ESCC, 5203/010, SMD.5, Emitter on pin 2

But table 7, ordering information correctly lists the options of the pin-out.

Yes, you can use your diagram with the red marked pin numbers for this part number.

Regards

/Peter

P.S.: It is permissible, but it is still not a good idea to reply by email to messages from the community, because the reply email usually sends all private data (telephone numbers, addresses, etc). This is then visible to everyone in this community, which is open to the public worldwide. To ensure data protection, you should therefore not reply by email, but via the community's web interface.

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.