What is the maximum external pull up resistor on a GPIO in order to minimize power consumption?

[jsisc.1]

Hi.

I want to use interrupts to wake up from STOP2 and minimize the power consumption.

The internal pull-up of 30k - 50K leaks about 100 uA when pulled to 3V3, so I was wondering how big can be a pull up in order to minimize this consumption. Ideally, placing a 1M resistor would decrease consumption to nanoamps.

I know that it is related to leakage current on the pin (I_lkg), but I don't get it. 

Thanks in advance

[jsisc.1]

I thought about that, and It works. But I need also a disconnection event.

Thanks.

[jsisc.1]

Thanks, JHOUD,

I get you, but I don't get the sequence of configuration to detect a connection and a disconnection event without consumption.

Imagin the next sequence using two GPIOs. 1 will be receiving interrupts and 2 just as an output.

State 0 - Jumper disconnected

Pin 1: Pulled up

Pin 2: "0"

State 1 - Connecting the jumper

Pin 1: Pulled up. Falling edge interrupt.

Pin 2: "0"

State 2 - Connected

Pin 1: "0". Pulled up so there is consumption. Rpu can be disabled by software to avoid it.

Pin 2: "0"

State 3 - Jumper disconnected

Pin 1: No pull up so, How to detect a Rising edge as a disconnection event?

Pin 2: "0"