Solved: I'm using a STM32F429I discovery with HAL drivers.... - STMicroelectronics Community

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You can just change the CCRx register directly. I don't think HAL has a function for doing only this. Pretty sure the LL library does.

For 50% duty:

TIMx->CCRx = (TIMx->ARR + 1) / 2;

For 25%/75% duty:

TIMx->CCRx = (TIMx->ARR + 1) / 4;

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4 REPLIES 4

You can just change the CCRx register directly. I don't think HAL has a function for doing only this. Pretty sure the LL library does.

For 50% duty:

TIMx->CCRx = (TIMx->ARR + 1) / 2;

For 25%/75% duty:

TIMx->CCRx = (TIMx->ARR + 1) / 4;

If you feel a post has answered your question, please click "Accept as Solution".

https://github.com/STMicroelectronics/STM32CubeF4/blob/master/Drivers/STM32F4xx_HAL_Driver/Inc/stm32f4xx_hal_tim.h#L1342 if you must have a HAL incantation for this.

JW

thanks for your answer, it works!!

I've find the solution in the following reply. Thanks for your support.