2023-02-28 10:19 AM
I am a 10yr Arduino IDE programmer and I have a cheap ST-Link V2 (Canaduino).
M5Stack provides a copy of the firmware and I would like to experiment with making it a stand alone MCU that could read inputs and respond with outputs. I would like to do this in Arduino V2 IDE as I am very familiar with this.
How feasible is this?!
-Terry
Solved! Go to Solution.
2023-03-01 01:22 AM
Welcome, @teastain, to the community!
After a quick look at the specification of the M5Stack Stamp-IO, it looks like the included STM32F030F4P6 can be programmed via the SWD interface included on the Stamp-IO - if the Stamp-IO has not been protected against this. On the bottom side, the SWD connections can be found as 3V3, C (SWCLK), D (SWDIO), R (NRST) and GND.
Regarding the ST-Link V2 (Canaduino), however, it should be noted that this is a clone of the ST-LINK/V2 with probably illegally copied firmware, so STMicroelectronics cannot and will not make any statement about its suitability or function. But with an original ST-LINK, debugging and programming could succeed.
If the problem is solved, please mark this thread as answered by selecting Select as best, as also explained here. This will help other users find that answer faster.
Regards
/Peter
2023-03-01 01:22 AM
Welcome, @teastain, to the community!
After a quick look at the specification of the M5Stack Stamp-IO, it looks like the included STM32F030F4P6 can be programmed via the SWD interface included on the Stamp-IO - if the Stamp-IO has not been protected against this. On the bottom side, the SWD connections can be found as 3V3, C (SWCLK), D (SWDIO), R (NRST) and GND.
Regarding the ST-Link V2 (Canaduino), however, it should be noted that this is a clone of the ST-LINK/V2 with probably illegally copied firmware, so STMicroelectronics cannot and will not make any statement about its suitability or function. But with an original ST-LINK, debugging and programming could succeed.
If the problem is solved, please mark this thread as answered by selecting Select as best, as also explained here. This will help other users find that answer faster.
Regards
/Peter