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LSM6DSO16IS: custom ISPU code with output in INT1 and INT2

cchen
Associate II

Hi,

I am working on a custom ISPU code for LSM6DSO16IS and I want to generate interrupts on INT1 and INT2. I checked all the examples in x-cube-ispu/Ispu/ism330is_lsm6dso16is at main · STMicroelectronics/x-cube-ispu generates an interrupt only on INT1.

Is it possible to generate interrupts on INT1 and INT2 at the same time?

 

Thanks a lot :)

Chen

1 ACCEPTED SOLUTION

Accepted Solutions
Federica Bossi
ST Employee

Hi @cchen ,

Yes, both INT1 and INT2 can be generated. The configuration should be set in the conf.txt: https://github.com/STMicroelectronics/ispu-examples/blob/master/ism330is_lsm6dso16is/template/ispu/conf.txt.

acc_odr 26

acc_fs 8

acc_mode high_performance

 

ispu_irq_rate 26

ispu_int1 enable

ispu_sleep_int2 enable

ispu_latch disable

 

algo 0 enable

algo_int1 0 enable

 

The configuration highlighted in bold should be removed or should be changed by putting “disable” as an argument: by default, on the template and on our examples, INT2 is used for the ISPU sleep signal. The configurations highlighted in italics in the template enable INT1 in general and then specifically for Algorithm 0. To use INT2, similar configurations should be put in, so:

ispu_int2 enable

algo_int2 0 enable

This is if you want to enable INT2 on algorithm 0 as well, otherwise just specify, instead of '0', the number of the algorithm for which you want to generate the interrupt on INT2.

In order to give better visibility on the answered topics, please click on 'Accept as Solution' on the reply which solved your issue or answered your question.

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2 REPLIES 2
Federica Bossi
ST Employee

Hi @cchen ,

Yes, both INT1 and INT2 can be generated. The configuration should be set in the conf.txt: https://github.com/STMicroelectronics/ispu-examples/blob/master/ism330is_lsm6dso16is/template/ispu/conf.txt.

acc_odr 26

acc_fs 8

acc_mode high_performance

 

ispu_irq_rate 26

ispu_int1 enable

ispu_sleep_int2 enable

ispu_latch disable

 

algo 0 enable

algo_int1 0 enable

 

The configuration highlighted in bold should be removed or should be changed by putting “disable” as an argument: by default, on the template and on our examples, INT2 is used for the ISPU sleep signal. The configurations highlighted in italics in the template enable INT1 in general and then specifically for Algorithm 0. To use INT2, similar configurations should be put in, so:

ispu_int2 enable

algo_int2 0 enable

This is if you want to enable INT2 on algorithm 0 as well, otherwise just specify, instead of '0', the number of the algorithm for which you want to generate the interrupt on INT2.

In order to give better visibility on the answered topics, please click on 'Accept as Solution' on the reply which solved your issue or answered your question.

Hi Federica,

I have followed your advice and managed to generate interrupts INT1 in "algo 0" and INT2 in "algo 1".

But it happens that when INT2 is 0, it only freezes all my ISPU Output data. And when INT2 is 1, it reads the ISPU Output data. The same does not happen with INT1.

I have no ideas on where to debug this problem, could you give me some advices please?

 

I am programming my code in STM32CubeIDE and testing it with STEVAL-MIK109V3 with adapter board MKI229A (LSM6DSO16IS) and showing my output value in MEMS Studio.

The configuration I set in conf.txt:

acc_odr 104
acc_fs 2
acc_mode high_performance

gyr_odr 104
gyr_fs 500
gyr_mode high_performance

ispu_irq_rate 104
ispu_int1 enable
ispu_int2 enable
ispu_latch disable

algo 0 enable
algo 1 enable
algo_int1 0 enable
algo_int2 1 enable

 

In the main.c inside the signal function "algo_00" it finish with 

if(int1_signal == 1){
   int_status = int_status | 0x1u;
}

And in function "algo_01":

if(int2_signal == 1){
   int_status = int_status | 0x2u;
}

I have not modified the function "int main(void)"

 

Thank you very much!