Posted on May 17, 2011 at 15:10Hi,
i already checked this example.
i do not understand how i can filter the source pin which initiated the interrupt.
the interrupt routine says:
{
if ((GPIO_ReadInputData(JOYSTICK_PORT) & JOYSTICK_LEFT_PIN) == 0x00)
{
GPIO_WriteReverse(LEDS_PORT, LED1_PIN);
}
if ((GPIO_ReadInputData(JOYSTICK_PORT) & JOYSTICK_RIGHT_PIN) == 0x00)
{
GPIO_WriteReverse(LEDS_PORT, LED2_PIN);
}
if ((GPIO_ReadInputData(JOYSTICK_PORT) & JOYSTICK_UP_PIN) == 0x00)
{
GPIO_WriteReverse(LEDS_PORT, LED3_PIN);
}
if ((GPIO_ReadInputData(JOYSTICK_PORT) & JOYSTICK_DOWN_PIN) == 0x00)
{
GPIO_WriteReverse(LEDS_PORT, LED4_PIN);
}
}
....
ReadInputData reads the complete port value, but i want to detect on 2 pins of the same port rising and falling edges independently.
for example: in my routine if one of the pins goes high (the other is low) it fires my interrupt routine and then i check with ReadInpuData the value. But if the other is high and the pin goes high, it will perform two actions if i would do something with ReadInputData and this ''if''-structure.
Now i'm using PortB for my second input to get really different interrupt sources which i can handle.
But i think there should be a more convenient way to do this only with one port.
