Flash Space calculations STM32L496RGT6

Looking into the available flash space on the chip:

For the 1Mbyte variant of the device the total number of bytes should be 1,024,000.

2,000 bytes * 512page = 1,024,000 bytes of flash memory.

End of Address Space - Start of address space = Amount of total space

0x080F FFFF - 0x0800 0000 = 0xF FFFF bytes = 0d1,048,575 bytes

Am I incorrectly calculation incorrect ? If not where's the missing 24,575 ?

Thanks

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Best answer by TDK

1MB = 1024^2 bytes

The flash length is 0x10 0000, which is 1024 * 1024 = 1048576 bytes = 1 MB.

TDKBest answer

1MB = 1024^2 bytes

The flash length is 0x10 0000, which is 1024 * 1024 = 1048576 bytes = 1 MB.

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