cancel
Showing results for 
Search instead for 
Did you mean: 

Can I pull-down boot0 with 10kOhm instead of having 3 pin jumper

abdelrhmatta
Associate

STM32f103
In the design guide it recommends to have something switching between vcc and gnd with 10kOhm series resistor, and i need my design to be grounded by default so i may not solder the header even, is it okay if i left the design like fig 1 instead of fig 2, and would it cause issues if i needed to pull it high?

2 REPLIES 2
gbm
Principal

No issue. You may pull it down with anything up to 100k and provide some contacts for connecting it to Vdd for bootloader activation.

You may short BOOT0 to ground directly with a PCB trace if you don't need to invoke the bootloader via hardware.

My STM32 stuff on github - compact USB device stack and more: https://github.com/gbm-ii/gbmUSBdevice
Peter BENSCH
ST Employee

The pull-up resistor has the advantage of allowing you to set the pin in question to a different level directly at the pin without creating a short-cut. If you are absolutely certain that you never want to switch the pin, you can also connect it directly to a fixed potential (e.g. GND for the BOOT pins) without a pull-up resistor. You can also omit the pull-up resistor if you use a switch/jumper.

Regards
/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.