Can I pull-down boot0 with 10kOhm instead of having 3 pin jumper

[abdelrhmatta]

STM32f103
In the design guide it recommends to have something switching between vcc and gnd with 10kOhm series resistor, and i need my design to be grounded by default so i may not solder the header even, is it okay if i left the design like fig 1 instead of fig 2, and would it cause issues if i needed to pull it high?

[gbm]

No issue. You may pull it down with anything up to 100k and provide some contacts for connecting it to Vdd for bootloader activation.

You may short BOOT0 to ground directly with a PCB trace if you don't need to invoke the bootloader via hardware.

[Peter BENSCH]

The pull-up resistor has the advantage of allowing you to set the pin in question to a different level directly at the pin without creating a short-cut. If you are absolutely certain that you never want to switch the pin, you can also connect it directly to a fixed potential (e.g. GND for the BOOT pins) without a pull-up resistor. You can also omit the pull-up resistor if you use a switch/jumper.

Regards
/Peter

[gregstm]

To minimise board space, I've always just used a single pull down resistor (no series resistor) with a test point/contact  (close to the micro) I can use to pull Boot0 high if required. I think it is a safer design to always have a pull down resistor. I personally would never connect Boot0 directly to ground, sometimes you need to pull Boot0 high to revive a stuck chip.

[TDK]

If you don't reassign the SWD pins, and that's how you program, there's little need to be able to pull BOOT0 high.