why Pointer is always (uint8_t *)?

[smhhadima]

Posted on September 12, 2015 at 12:45

why Pointer is always (uint8_t *)?

does it mean the pointer will never exceed 255?

[Tesla DeLorean]

Posted on September 12, 2015 at 14:34

It's a pointer to 8-bit values, the pointer itself is 32-bit wide and can address 4GB 

[smhhadima]

Posted on September 12, 2015 at 21:15I am using STM32F407When I pass a pointer of a string to a function, should I used ( uint32_t * ) instead of (uint8_t*)?Because all the examples that I see uses (uint8_t*)

[Tesla DeLorean]

Posted on September 13, 2015 at 01:19

The concept of pointers transcends the use of an STM32, you might want to review the K&R chapter on pointers, or that of your primary text.

It's pointing to a series of bytes/characters, these are 8-bit in size. If you used (uint32_t *) you'd be pointing at 32-bit words. sizeof(uint8_t) = 1  // The thing it's pointing AT sizeof(uint8_t *) = 4 // The pointer to it, an ADDRESS sizeof(uint32_t) = 4 // The thing it's pointing AT sizeof(uint32_t *) = 4 // The pointer to it, an ADDRESS All WHAT examples?