stm32U073 tamper 4 push button will hardfault

[russell_hsiao]

hi ,

i enable tamper4 and RTC in stm32mx and only enable bit RTC_CR_TAMPTS, TSE=0
no other code add into rtc.c or tamper.c 

Using  debug mode to clear TSF and CTAMP4F.
when push button will happen hard fault.  
Only two code  in main while loop "led" and "hal_delay", if i remove HAL_Delay , will not happen . 
someone can help me?

HAL_Delay(1000);

HAL_GPIO_TogglePin(GPIOA,GPIO_PIN_11);

[Saket_Om]

Hello @russell_hsiao 

Please check the article below to debug hardfault:

How to debug a HardFault on an Arm® Cortex®-M STM3... - STMicroelectronics Community

Could you share your .ioc file please then we can assiste you more effectively. 

[russell_hsiao]

hi , i upload my .ioc
and here i disable  those bit. 

/* USER CODE BEGIN RTC_Init 2 */

__HAL_RTC_TIMESTAMP_DISABLE(&hrtc);

CLEAR_BIT(RTC->CR, RTC_CR_ITSE);

CLEAR_BIT(RTC->CR, RTC_CR_TAMPALRM_TYPE);

/* USER CODE END RTC_Init 2 */

[Saket_Om]

Hello @russell_hsiao 

Could you check without WWDG init please? 

[russell_hsiao · Accepted solution]

hi Saket_Om,
Try disable WWDG, but still happened.
I follow how to debug to trace hard fault cause by "HAL_Delay".
Now use TIM to replace HAL_Delay. It seems work good.