Let's estimate some figures:
In the datasheet you'll find a maximum supply current of 5mA @ 5.5V and 20MHz = 27.5mW.
This power would lead to a temperature difference of 5.5K if we assume a (really, really bad) value of 200K/W.
Reading the whole content of a 32Kbit EEPROM at 20MHz would take about 2ms or so, after that it typically goes to standby with max 5µA = 27.5µW, which then generates a negligible increase in temperature.
Have you got any good reason that someone provides the exact thermal resistance of such an EEPROM?
Kind regards,
/Peter
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