2026-01-26 5:56 PM - edited 2026-01-27 4:47 AM
Hello,
I am back to working on testing a custom PCB with the ST25R3916B chip included on it! This custom hardware is setup for the differential antenna connection. The coil to be attached to this custom PCB is different than the one included on the eval board for the ST25R3916B chip. The pads for the matching components are all included but the components still need to be calculated for the coil. I have access to a VNA and can follow the procedure for matching...
Regarding the matching component calculations...I have reviewed the AN5276 application note and have some questions &/or statements to confirm. In general I don't fully understand the "target impedance" to match antenna to. For my application I'm trying to maximize power transfer through a wire wound TX coil.
My main question is the following:
For maximum power transfer... My main questions are the following:
Thank you in advance. Looking forward to response.
Solved! Go to Solution.
2026-02-17 12:36 AM
Hello Wrig0421,
It is not clear for me which role the ST25R3916B will play?
Do you want to use it as a transmitter or as a receiver?
If Tx only, yes you can use the AN5276 as a guideline for matching.
What will be used for the Rx device? I propose that the whole matching is done when both (Tx and Rx) antennas are at their final place.
Regarding your questions:
Transmitting with or without modulation will not significantly impact the power transfer.
add 1.) What you are describing is not possible with the device. The Driver current through the transmitter should not exceed 350mA, as stated in the datasheet. It is possible to bypass the internal regulator which allows the driver current up to 500mA. Matching the antenna to the same impedance as the driver will cause a current above 600mA at an efficiency of ~50%. Which means, if you output 1,7W also 1,7W will be dissipated by the device. At a thermal resistance of your PCB of ~60°C/W it means a self-heating of ~102°C.
add 1.2.) There is no internal amplifier. The ST25R typically consists of an internal LDO which generates the driver voltage (VDD_DR). The normalized driver resistance is typically set to 0 which is the minimum and gives the highest efficiency.
The calculation of the dissipated power in the device can be found in AN5584.
add 2.) The impedance mentioned in the AN is an example. Some customers want to spend more power, some less. The AN should guide them how to select the matching impedance.
Add 4.) pt_res and ptm_res is the driver resistance in card emulation mode. (=> are you using the device as Rx device?) For Reader mode d_res must be considered. pt_res and ptm_res do not have an impact.
Add 5.) No, See question 4.
Your questions:
I would recommend starting at a Matching impedance of 9Ohm. The current consumption should be right below 350mA and the internal regulator can be used.
You may also want to look at a more recent device. The ST25R300 can output 500mA continuously at 6V VDD which allows an output power of around 2.2W and a more efficient driver resistance.
BR Travis
2026-02-17 12:36 AM
Hello Wrig0421,
It is not clear for me which role the ST25R3916B will play?
Do you want to use it as a transmitter or as a receiver?
If Tx only, yes you can use the AN5276 as a guideline for matching.
What will be used for the Rx device? I propose that the whole matching is done when both (Tx and Rx) antennas are at their final place.
Regarding your questions:
Transmitting with or without modulation will not significantly impact the power transfer.
add 1.) What you are describing is not possible with the device. The Driver current through the transmitter should not exceed 350mA, as stated in the datasheet. It is possible to bypass the internal regulator which allows the driver current up to 500mA. Matching the antenna to the same impedance as the driver will cause a current above 600mA at an efficiency of ~50%. Which means, if you output 1,7W also 1,7W will be dissipated by the device. At a thermal resistance of your PCB of ~60°C/W it means a self-heating of ~102°C.
add 1.2.) There is no internal amplifier. The ST25R typically consists of an internal LDO which generates the driver voltage (VDD_DR). The normalized driver resistance is typically set to 0 which is the minimum and gives the highest efficiency.
The calculation of the dissipated power in the device can be found in AN5584.
add 2.) The impedance mentioned in the AN is an example. Some customers want to spend more power, some less. The AN should guide them how to select the matching impedance.
Add 4.) pt_res and ptm_res is the driver resistance in card emulation mode. (=> are you using the device as Rx device?) For Reader mode d_res must be considered. pt_res and ptm_res do not have an impact.
Add 5.) No, See question 4.
Your questions:
I would recommend starting at a Matching impedance of 9Ohm. The current consumption should be right below 350mA and the internal regulator can be used.
You may also want to look at a more recent device. The ST25R300 can output 500mA continuously at 6V VDD which allows an output power of around 2.2W and a more efficient driver resistance.
BR Travis