LSM6DSM Power Draw at Different Voltages
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‎2022-06-10 8:58 AM
Hello,
I am looking at the LSM6DSM datasheet for power draws. Here is an example
- Accelerometer Current Consumption @ ODR=52Hz
- VDD = 1.8 V
- Current = 25 uA
- Power = VDD*Current = 45 uW
Does the current required by the LSM6DSM accelerometer change if VDD is toward the upper end, say, 3.3 V? Should I expect lower, or higher, power draws? Basically fill out the following:
- Accelerometer Current Consumption @ ODR=52Hz
- VDD = 3.3 V
- Current = TBD uA
- Power = VDD*Current = TBD uW
Thanks in advance!
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‎2022-06-17 8:49 AM
Hi @CMehr.1​ ,
please consider that the main increase in power consumption is given by a change in the ODR frequency.
A change in Vdd from 1.8V to 3.3V qill increase the accelerometer power consumption by about 2 / 3 uA.
- VDD = 3.3 V
- Current = 27uA uA
- Power = VDD*Current = 90 uW
If my reply answered your question, please click on Select as Best at the bottom of this post. This will help other users with the same issue to find the answer faster.
-Eleon
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‎2022-06-17 8:49 AM
Hi @CMehr.1​ ,
please consider that the main increase in power consumption is given by a change in the ODR frequency.
A change in Vdd from 1.8V to 3.3V qill increase the accelerometer power consumption by about 2 / 3 uA.
- VDD = 3.3 V
- Current = 27uA uA
- Power = VDD*Current = 90 uW
If my reply answered your question, please click on Select as Best at the bottom of this post. This will help other users with the same issue to find the answer faster.
-Eleon
