2026-04-15 6:13 AM - last edited on 2026-04-15 6:17 AM by mƎALLEm
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手册上写着在高分辨率模式下功耗 90 µA,在低功耗模式下功耗低于 1 µA。可是我用示波器串联电阻抓出来的功耗接近1MA,并且未使用MCU配置传感器时功耗就已经接近这个值了。传感器通过开发板的3.3V接口进行供电。电路图如下所示,哪里存在问题呢?
Translation:
The manual states that the power consumption is 90 µA in high-resolution mode and less than 1 µA in low-power mode. However, the power consumption I measured with an oscilloscope using a series resistor is close to 1 mA, and this value is already close to the power consumption even without configuring the sensor using the MCU. The sensor is powered through the development board's 3.3V interface. The circuit diagram is shown below. Where is the problem?
Solved! Go to Solution.
2026-04-15 8:39 AM
Why do you have pullup resistors on the interrupt pins?
2026-04-15 8:39 AM
Why do you have pullup resistors on the interrupt pins?
2026-04-16 12:24 AM
looking forward to the answer here.
2026-04-16 12:38 AM
Hi @御宸 ,
Your schematic seems correct.
However, 4K7 on the I2C lines is slight higher. You could try to reduce them.
2026-04-17 12:42 AM
您好,感谢您的回复!
我把中断引脚的上拉电阻移除后,板上电流的功耗确实改善了很多,但是还是存在一个固定功耗大概200uA(没有外接其他任何单片机,只测试这款传感器的功耗)请问还可能是电路方面的哪些原因呢?
再次感谢您的回复!
2026-04-17 1:41 AM
您好,感谢您的回复!
我把中断引脚的上拉电阻以及4k7的电阻移除后,板上电流的功耗确实改善了很多,但是还是存在一个固定功耗大概200uA(没有外接其他任何单片机,只测试这款传感器的功耗)请问还可能是电路方面的哪些原因呢?
再次感谢您的回复!
2026-04-17 8:48 AM
2026-04-17 10:30 AM
OK, using your information, the current dropped 800 uA when removing two 10K pullups on the interrupt lines. So this implies that the pullup (and VCC) voltage is ~10K * 400 uA ~ 4V.
However, the max supply voltage for the LIS2DW12 per the data sheet is 3.6 V...so I would guess that you are using a 1S LiPo battery to power the LIS2DW12 directly, which will destroy it, or at least cause an anomalous power draw....