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Current consumption in VL53L0X in single ranging

lolo_2020_2020
Associate

Hi folks,

I am currently testing the VL53L0X sensor and reading the datasheet. Is the current consumption of the sensor 19 mA in the single ranging scenario, or is it calculated for continuous ranging? I'm not clear on this point.

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
John E KVAM
ST Employee

It's 19ma when it is ranging.

So if you range 5 times per second with a 20ms integration time, assume 19mA for 20ms * 5. The rest of the time the sensor consumes much less. One would get 19mA *100ms or about 1.9mA average consumption. As you can see the number of ranges you take and how long you integrate makes the difference.

 

- john


If this or any post solves your issue, please mark them as 'Accept as Solution' It really helps. And if you notice anything wrong do not hesitate to 'Report Inappropriate Content'. Someone will review it.

View solution in original post

1 REPLY 1
John E KVAM
ST Employee

It's 19ma when it is ranging.

So if you range 5 times per second with a 20ms integration time, assume 19mA for 20ms * 5. The rest of the time the sensor consumes much less. One would get 19mA *100ms or about 1.9mA average consumption. As you can see the number of ranges you take and how long you integrate makes the difference.

 

- john


If this or any post solves your issue, please mark them as 'Accept as Solution' It really helps. And if you notice anything wrong do not hesitate to 'Report Inappropriate Content'. Someone will review it.