2026-04-29 7:04 PM - last edited on 2026-04-29 11:09 PM by Peter BENSCH
Hi,
When performing two measurements per second, how can the power consumption of the VL53L0x be reduced? Is a single measurement or continuous timed measurements preferable? I adopted continuous timed high-speed measurements, setting the measurement duration to 22 ms with a 900 ms interval between measurements, resulting in an average measured current of 19 mA (according to the specification). Based on this, I calculated the average power consumption.
(22 mS × 19 mA + 5 μA × 878 mS) / 900 mS = 0.4693 mA. I don't understand why others can achieve 20 μA.