2026-04-29 7:04 PM - last edited on 2026-04-29 11:09 PM by Peter BENSCH
Hi,
When performing two measurements per second, how can the power consumption of the VL53L0x be reduced? Is a single measurement or continuous timed measurements preferable? I adopted continuous timed high-speed measurements, setting the measurement duration to 22 ms with a 900 ms interval between measurements, resulting in an average measured current of 19 mA (according to the specification). Based on this, I calculated the average power consumption.
(22 mS × 19 mA + 5 μA × 878 mS) / 900 mS = 0.4693 mA. I don't understand why others can achieve 20 μA.
2026-05-05 8:57 PM
Hi
This is repeat request, let me share the answer here belwo.
You choice "continuous timed" mode is the correct mode. and you power consumption calculation method is absolutely correct. Normally the power consumption is mainly consumed during ranging window.
To reduce the power further, you can try to decrease the ranging time(Timing budget) and increase the idle time(InterMeasurmentPeriod).
Br
Zhiyuan.Han