STM23f303-re vs STM32F303-ze virtual comm port

[DPeki.1]

Hello,

I have a project working on the F303-re Nucleo board. I want to run it now on the F303-ze Nucleo board. Apparently virtual com port doesn't work the same on the ZE as it does on the RE. I can take a new RE board, copy the binary file to the RE board and the app starts communicating on the virtual comm port. I do the same thing on the ZE board and I get no virtual comm port communications.

I assume I'm missing a jumper or solder bridge configuration that will allow the ZE to start virtual comm port communications. What am I missing?

Thanks,

• Dave

[Imen.D]

Hello @DPeki.1​ and welcome to the Community :),

Do you see the device in your device manager as serial interface?

Maybe that issue is linked to the ST-Link firmware version.

So, try to upgrade the ST-Link firmware version, then disconnect and connect your board.

Have a look at the AN4879 USB hardware and PCB guidelines using STM32 MCUs, it may help you.

When your question is answered, please close this topic by choosing Select as Best.

Imen

[DPeki.1]

Yes Imen,

It does show up as a serial interface (Comm 5). And the file exloper shows the device as Nod-f303ze. That looks the same as a F722ze board that I have where the virtual comm port works correctly (comm 7 and a different device name in file explorer - f722 vs f303). On the 722, solder bridges SB132 and sb133 have been removed. Those relate to USB useage, not virtual comm port as I read it, right?

Should I be able to load exactly the same bin file between the 303re and the 303ze? I would assume so since they're the same processor.

I will look at the document you referenced.

Thanks,

Dave

[DPeki.1]

I guess the basic question is should code that runs on the f303re run on the f303ze? Can I load the same binary on both boards and expect the same operation? If the answer is yes, I've got a bad ZE board. If the answer is no, I need to track down the differences. (I know the connector layout is different.)

[KDJEM.1]

Hello @DPeki.1​,

A similar question is already asked here. And the best answer is already provided by @Peter BENSCH​. 

When your question is answered, please close this topic by choosing Select as Best. This will help other users find that answer faster.

Kaouthar