What is the 0R in front of the resistors

[Nimai_Singhal]

Can someone please help me find the value of 0R, as I am trying to use the CAN FD, but I am not able to figure out the values of the resistor.

[TDK]

0R means 0 Ohms. It's just a jumper--no resistance.

 

[Nimai_Singhal]

Thank you so much.

[FGUIT]

Hello,

To protect this CAN transceiver against ESD and EOS, you can add ESDCAN04-2BLY or ESDCAN04-2BWY on CANH and CANL, as close as possible to P2 connector. Layout is important for ESD protection devices, you can find layout tips on AN5686.

Best regards.

Fabrice.

 

[Nimai_Singhal]

Thank you so much,
I will definitely keep this in mind while creating my CAN-FD.

[mƎALLEm]

Hello @Nimai_Singhal and welcome to the community,

1- This is not a ST product. You need to ask NXP for that. 0R = 0ohm. It's just a solder bridge.

2- TJA1050 is not intended to be used in CAN-FD mode i.e. > 1Mb/s. From the datasheet:

If you are using STM32 having FDCAN interface, you can use it only in Classic mode.

 

[Nimai_Singhal]

Thank you so much.

Can you recommend some chips that may be good for CAN-FD purposes?

[mƎALLEm]

@Nimai_Singhal 

No need to post several posts. You can Tag everyone here using @ and say what you want in the same post.

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@Nimai_Singhal wrote:

Thank you so much.

Can you recommend some chips that may be good for CAN-FD purposes?

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That depends on the bitrate you will be using in the data phase.

MCP2562FD could reach 8Mb/s. It's already used on STM32H743I-EVAL board:

 

You can refer to this article: STM32 FDCAN running at 8 Mb/s on NUCLEO boards

Hope that helps.