Is it true that STM32WLE5 (UFBGA73) UART programming is over pin E5 (TX) and C8 (RX)?
Application note AN2606, on page 380. It says that in the default bootloader, USART is used on pin PA9 (E5)(TX) and PA10 (C8)(RX). However, when I select USART1 in STM32CubeMX, in mode Asynchronous, pins E1 (TX) and C3 (RX) are used. USART programming is not possible with the default bootloader then, right?
