Difference between object.setVisible(false) and remove(object)

[Tuoman]

If user wants to make object invisible, which method is the most efficient, e.g. in terms of performance or memory usage?

Generally, in which cases should use setVisible true/false vs. add/remove?

Is it so that the only difference is that remove/add modifies drawing order, but otherwise they are equal? (I.e. performance to draw removed or invisible objects are both neglible)

In that case add/remove should only be called in init (or if drawing order must be changed), and setVisible afterwards...

[qq3g7bad]

Hello, Tuoman.

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> Is it so that the only difference is that remove/add modifies drawing order, but otherwise they are equal? 

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No. It differs in several points. I will write my understanding.

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`setVisible()` is a function to show a instance based on `Drawable` class.

•  There are no effect to memory usage because `setVisible()` work on only its visibility.

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`remove()` is a function to delete a instance based on `Drawable` class for future rendering.

•  `remove()` is not a function of `Drawable` but of `Container` (Screen class has its own "root container". See here). 
•  If a instance based on `Drawable` is removed from `Container`, it result in being removed from memory.
•  When a user call `add()` for redrawing some widgets, TouchGFX might be acquire a new memory region for those widgets.

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So I think as follows.

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• If you switch visibility of a component repeatedly, it is good to use `setVisible()`.
• If you delete some instance and never use it, it is good to use `remove()`.

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