timer interrupt

[mohammad arabloo]

Posted on January 01, 2017 at 16:39

hi

I have a stm32f4 discovery board and i use stm32 cube.

I want to create a 400ns interrupt but it doesn't less than 2.5us.

my initialization are:

TimHandle.

Init

.

Period

=

1

;

TimHandle.

Init

.

Prescaler

= 0;

TimHandle.

Init

.

ClockDivision

=

0

;

 can you help me?

thank you

[Khouloud GARSI]

Posted on January 03, 2017 at 11:24

Hi Mohammad,

All STM32F4 devices give you the ability to create a 400ns interrupt.

Could you please tell me the value of the timer clock you are using.

Khouloud.

[mohammad arabloo]

Posted on January 04, 2017 at 11:30

Dear khouloud,

It is 48mhz

[Tesla DeLorean]

Posted on January 03, 2017 at 13:00

Your goal is unrealistic.

[Jeroen3]

Posted on January 03, 2017 at 15:11

Indeed. With the fastest F4  running from SRAM you only have 72 ticks until the next interrupt.

(eg: 400e-9 / (1/180e6) is 72) 

You will have the inevitable 2x12 ticks of latency, meaning there are only 48 cycles for your assembly written ISR to perform what it want to do. Worst case you can go up to 54, but you'll be tail-chaining forever.

See this article in the 

http://infocenter.arm.com/help/index.jsp?topic=/com.arm.doc.ddi0439b/ch03s09s01.html

.

[mohammad arabloo]

Posted on January 04, 2017 at 11:36

Dear Jeron3,

your calculation is correct, but it does not matter

it can't less than 2.5us

[Oliver Beirne]

Posted on January 03, 2017 at 16:53

Hi

arabloo.mohammad

I have moved your post to the

https://community.st.com/community/stm32-community/stm32-forum?sr=search&ampsearchId=172c65f8-4e7d-4345-9952-242faac28f6d&ampsearchIndex=0

where you should post any future product related questions you have.

Thanks

Oli