QSPI dual flash - addressing

[da66en]

I'm porting a QSPI bootloader over from a design that 1 flash chip to 2 flash chips in parallel (10 bit mode, common CS).  I am not sure how the addressing works now that there are 2 chips in parallel.  I feel like the only thing STM32 says on the matter is in AN4760 in that even bytes goto one flash 1 and odd bytes goto the flash 2.

If I have something that is addressed at 0x1000 internally by the STM32, when sending QSPI commands to write or erase to the QSPI do I need to double the address (to 0x2000) first?  Or does the QSPI interface in the STM32 already do that for me?

 

[Tesla DeLorean]

The implementation is a bit clumsy and confusing.

In "DUAL" mode both devices need to be the same, content is multiplexed at a BYTE level. So all send and receive commands are sent to both devices and the data sent and received alternates between them.

The command and address goes to both devices in parallel. The address is divided by TWO

Pages that were 0x100 or 0x1000 will now be 0x200 or 0x2000, see also addresses for erase, etc.

The status comes back in pairs, and devices might not be synchronized, ie one might complete the erase before the other, you need to wait for BOTH to complete fully.

To erase the second 64KB block in both devices (0x10000 on a single device), you pass the 0x20000 address, and it will erase 128KB across both devices.

[Zakba.1]

hello, I need to change the qspi flash from single to dual mode...Does it make any difference in the loader? Can I use my previous loader for programming both flashes? (no changes in flash1 pins)

thank you in advance for your answer

[da66en]

Thanks for the excellent writeup.

So if something is at address at 0x1000 on the STM32, I should pass 0x500 to the QSPI command?

For addressing, do I have to do that division manually or does the QSPI interface already do that for me if I'm in dual port mode?

[Tesla DeLorean]

The QSPI peripheral does the address division, so the address you pass as a parameter is divided by 2 on the wire, A0 would then select one device or the other, although I wouldn't rely on that. Do everything with the expectation that both devices are involved.

As per my example you set Address = 0x20000, the devices see 0x10000 on the wire.

BTW 0x1000 / 2 = 0x800

[Tesla DeLorean]

Write Page (0x02) which was 256-bytes is now effectively 512-bytes at 512-byte boundaries, ie 0x0000,0x0200,0x0400,..