How to show data received by UART to graph?

[nsabo.1]

Hi, I want to receive data by UART and display them by graph.

Here is my code:

```

 HAL_UART_Receive_IT(&huart1,(uint8_t*)RxBuf,1);

RxBuf[1]=r1[i];

```

and show by graph:

```

  if(i<256){

dynamicGraph1.addDataPoint(r1[i++] );

}else

i=0;

```

the problem is a straight line shown and not correct.

[Karl Yamashita]

You need to fix your code. RxBuf holds your value already when you get an interrupt. So you're graphing the value of r1, not RxBuf value.

[Tesla DeLorean]

RxBuf[0] would contain the data, you'd need to wait for the callback for the data to be present

[nsabo.1]

Thanks for your help.

Receiving data by UART and display it by TOUCHGFX cause some lost data in my screen, graph is not displayed correctly.

There are 2 boards one which is been receiving the signals by sensors and the second one is LCD board which has been configured by TOUCHGFX.

I want to receive data by UART from the first board and show them in LCD.

But some graph is not shown correctly.

Here is the code:

```

HAL_UART_Receive_IT(&huart1,(uint8_t*)RxBuf,20);

HAL_UART_RxCpltCallback(&huart1);

   HAL_Delay(1);

```

I put ```HAL_Delay(1); ``` in order to receive data correctly but it does not make sense.

And the data shown by graph:

```

   if(i<123){

dynamicGraph1.addDataPoint(RxBuf[1]+25);

}else

i=0;

```

How can I solve it?

Thanks again.

[Karl Yamashita]

You're posting incomplete code that makes no sense. Copy and paste exactly how you've written your code. And use the code snippet formatting by clicking on the </> icon so you're showing something like this below

void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart)
{
	// your complete code 
}