Converting date on GPS ?

[antonius]

Dear Members,

How can I convert date on GPS ?

UTC date 60819

into

6-August-2019 ?

thanks

[Tesla DeLorean]

Couldn't you divide by 100 and 10000 to extract the DD, MM and YY fields, and add 1900 or 2000 depending if YY is below 80

​

[antonius]

int day,month,year;
 
 day = date/10000;
 
 month = date/100-(day*100);
 
 year = date/100-((day*100)+month);
 
 printf("======================GPRMC PARSING =================\r\n");
 
 printf("UTC date %x \r\n",date);
 
 printf("Day %u-",day);
 
 printf("Month %u-",month);
 
 printf("Year %u-",year);
 
 printf("\r\n");
 
 printf("====================== D O N E !=================\r\n");

am I right ?

Thanks

[Tesla DeLorean]

>> am I right ? correct me ?

Put the code in a function, and run test cases against it.

The year computation is broken

[antonius]

correct me ?

   day = date/10000;

         month = date/100-(day*100);

         year = date/100-((day*100)+month);

[antonius]

How can I get the day name ? (Monday,Tuesday, etc ), still using divider ?

Thanks

[Tesla DeLorean]

It gets significantly more complicated,​ you'd need to convert into a Julian date number or Unix time, and extract the day from that.

[antonius]

I got this formula but if it's outside if, it's changing the date, I try inside if

 if (year < 80) year += 2000; else year += 1900;
 
 printf("Day %2d Month %2d Year %4d\n",day, month, year);
	printf("Month Name: ");printf(month_name[month-1]);printf("\r\n");
	printf("Date : %2d-",day);printf(month_name[month-1]);printf("-%2d",year);printf("\r\n");
	//weekday name
	int weekday = (day += month < 3 ? year-- : year - 2, 23*month/9 + day + 4 + year/4- year/100 + year/400)%7;
		printf("Weekday : %d \r\n",weekday);
	 printf("Weekday name : %s \r\n",weekday_name[weekday-1]);

what do you reckon ?