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TSosi.1
Associate III
March 2, 2022
Solved

Problem entering the bootloader using the STM32H753 and pattern 8

We are using the STM32H753 and cannot enter the bootloader using pattern 8.

AN2606 states that when BOOT0 is low and the option byte BOOT_ADD0 is 0x0040, then the bootloader is activated.

Does this work for the STM32H753?

Pattern 8

0693W00000KbAw4QAF.pngOption byte set to 0x0040 in STM32CubeProgrammer

0693W00000KbAxgQAF.png 

Thanks for your help!

This topic has been closed for replies.
TDK
TDKBest answer
March 2, 2022

For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.

0693W00000KbB72QAF.png 

Pattern 10:

0693W00000KbB7CQAV.png

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4 replies

TDK
TDKBest answer
March 2, 2022

For the H74xxx/75xxx bootloader, AN2606 says the bootloader is activated by pattern 10, not pattern 8.

0693W00000KbB72QAF.png 

Pattern 10:

0693W00000KbB7CQAV.png

"If you feel a post has answered your question, please click ""Accept as Solution""."
TSosi.1
TSosi.1Author
Associate III
March 2, 2022

Thank you again TDK! I learned twice today.

TSosi.1
TSosi.1Author
Associate III
March 2, 2022

Ok I tried this again. With my setup, I seem to have trouble entering into the bootloader on a power cycle. If I reset the processor by pulling NRST low and releasing I can communicate with the bootloader.

Thanks TDK for your help.