Solved
netconn_connect() for TCP/IP connection is blocking at osSemaphoreAcquire(TxPktSemaphore,...) on my STM32F746ZG-Nucleo
I try to implement a TCP/IP client on my STM32F746ZG-Nucleo.
Before the last update it was working. But no more now.
The first pass I always get a ERR_RTE because the ethernet link is not up. So I tried to connect each 5 secondes 5 times.
But the second pass, the link is up and everything seems good except one thing.
The program stay blocked on trying to acquire the semaphore :
HAL_ETH_Transmit_IT(&heth, &TxConfig);
while(osSemaphoreAcquire(TxPktSemaphore, TIME_WAITING_FOR_INPUT)!=osOK)
{
}
HAL_ETH_ReleaseTxPacket(&heth);Even if I wait 5 sec before trying to connect at the start, it will stay blocked at the exact same line.
I tried to add "netconn_set_nonblocking(conn, true);" but doesn't change anything.
Here is my configuration :
void StartDefaultTask(void *argument)
{
/* init code for LWIP */
MX_LWIP_Init();
/* USER CODE BEGIN 5 */
allInitCompleted = true;
/* Infinite loop */
for(;;)
{
osDelay(100);
}
/* USER CODE END 5 */
}And the function called my client thread to start the connection :
void ComChanEth::openConnection() {
err_t err;
setState(COMCHAN_CONNECTING);
// Create a new connection identifier
conn = netconn_new(NETCONN_TCP);
netconn_set_nonblocking(conn, true);
if (conn)
{
// Bind connection to the port number 7 (port of the Client)
err = netconn_bind(conn, IP_ADDR_ANY, MY_ETH_PORT);
if (err == ERR_OK)
{
for(uint8_t nbTry = 0; nbTry < MAX_TRY_ETH_CONNECT; nbTry++)
{
// Start TCP/IP connection
err = netconn_connect(conn, getServerAddress(), getServerPort());
// If the connection is established, exit the loop
if (err == ERR_OK)
{
setState(COMCHAN_CONNECTED);
break;
}
else
osDelay(5000); // Retry in 5 seconds
}
// If the connection has been established after 5 try, delete the connection
if (err != ERR_OK)
closeConnection();
}
else
{
// If the binding wasn't successful, delete the netconn connection
closeConnection();
}
}
}Does anyone have an idea ? or need more information to help me ?