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Best answer by Tesla DeLorean

It is just memory within the processors addressable space, just use memcpy() or pointers like you would with any other memory.

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Tesla DeLorean
Tesla DeLoreanBest answer
Guru
April 6, 2019

It is just memory within the processors addressable space, just use memcpy() or pointers like you would with any other memory.

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oleg_sidorovich_1981
Associate III
April 6, 2019

Exactly !! Thank.

S.Ma
Principal
April 6, 2019

uint8_t * pu8 = 0xtheadresstoreadas32bit;

uint8_t byte = *pu8;