CDC_Receive_FS max speed and how to accomplish it?

Hello guys,

I'm wondering how to accompish CDC_Receive_FS max speed, because as i understand the max Endpoint IN & OUT Packet size is 64 bytes, so i will need to receive around 4gb from the host, if it will take 1-2 days - i am okay with it. The problem is that i dont know how to make i properly, what i am doing now is looping in an endless loop and executing the cmd in a first byte of the 64 bytes package:

while (1)
 
 {
 
if (UserRxBufferFS[0] == 0x96) // 96 in the first bytes is the cmd and rest 63 bytes is the data.
 
{ 
 
 for(uint32_t i = 0 ; i <= 63 ; i++) 
 
{
 
	kyky[count1 + i] = UserRxBufferFS[i+1];
 
}			 
 count1 += 63;
 
if (count1 == 315)
 
{
count1 = 0;
WRITE_LEAF();
}
UserRxBufferFS[0] = 0;		
		}
 }

so what the code do, it is receiving 1byte cmd + 63 bytes data, and store it in the array buffer then after it receive 315 bytes it goes to the next sub WRITE_LEAF.

there are the two huge problems, the first one it is odd data length, i have to do more calcutaions on the host side because of it.And second one is the speed is too slow.

Any ideas, maybe some examples "how to do it properly"