Skip to main content
lk.dgironi
Associate III
January 14, 2022
Solved

STM32F103C8 production board schematic

  • January 14, 2022
  • 10 replies
  • 20563 views

I'm working on a board design with a STM32F103C8. First time for me to build a PCB with STM32, I've always worked with "blue pill" boards.

Not sure about BOOT wiring. The firmware will be uploaded using STM32CubeProgrammer. The board should startup using the internal firmware.

Only HSE External Crystal is used, 8Mhz.

PROG connect is used for programming/debugging.

Can you confirm this design will work? Thanks!

Note: first post here, so excuse me if I'm doing wrong.

This topic has been closed for replies.
Best answer by lk.dgironi

Solved.

Schematic attached.

10 replies

Peter BENSCH
Technical Moderator
January 14, 2022

Welcome, @Davide G_Oironi​, to the community!

  • C2, C3 seems to be a bit large, check AN2867 for correct values for your crystal
  • R10 should not be necessary
  • add a 100nF capacitor between NRST and GND
  • R9 is also not required

Good luck!

Regards

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
TDK
Super User
January 14, 2022

You should have a bulk 4.7uF capacitor on VDD somewhere.

Don't be afraid to use multiple GND and +3V3 symbols on your schematic to increase readability.

"If you feel a post has answered your question, please click ""Accept as Solution""."
lk.dgironi
Associate III
January 14, 2022

Thank you

@Peter BENSCH​ 

1)

According to AN2867 if I'm right I should apply the 3.3 Load Capacitance formula

Supposing Cs 5pF, which I think is a common value for "standard" PCB, my oscillator should have by datasheet 20pF Load Capacitance, so (Cl1*Cl2)/(Cl1+Cl2)=20pF-5pF and Cl1==Cl2 => Cl1,Cl2=30pF

Does it sound right?

2)

Thank's to you I've look at the datasheet, the NRST already has a RPU resistor, so R9 could be removed

3)

done

4)

I've fond R10 in other schematics, never seen that on my AVR experience, I've to investigate why others (in blue pill for example) use this resistor

@TDK​ 

Yes, I've a 10uF on the supply sheet.

You are right, readability is not that much with that few VDD and GND points.

Find schematic updated attached

Peter BENSCH
Technical Moderator
January 14, 2022

The feeback resistor was used in the last century in oscillator circuits that did not have an internal one. However, the STM32s have had this feedback resistor built in since the STM32s era began in 2007.

Why it was used in the Blue Pill... only its developers know.

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
lk.dgironi
Associate III
January 14, 2022

only its developers know :face_with_tears_of_joy: that's right :)

Thank you again.

About the 1) formula, is that right for a 20pF Load Capacitance? By the way the oscillator is a Fundamental one like specified in the AN2867 paper.

Peter BENSCH
Technical Moderator
January 14, 2022

1: yes, 30pF sounds reasonable if CL is actually 20pF (didn't expect a crystal with such a huge load capacitance). 4..5pF for CS are quite common values.

Good luck!

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
lk.dgironi
Associate III
January 14, 2022

edit:

~ the schematic of this reply is not correct ~

Peter BENSCH
Technical Moderator
January 14, 2022

Please open the shortcut from NRST to VDD.

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
lk.dgironi
Associate III
January 14, 2022

Done below

lk.dgironi
lk.dgironiAuthorBest answer
Associate III
January 14, 2022

Solved.

Schematic attached.

Peter BENSCH
Technical Moderator
January 14, 2022

Now it looks ok.

Regards

/Peter

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
Piranha
Principal III
January 15, 2022

Take a note that on 2 layer boards the stray capacitance is significantly smaller than on 4 or more layer boards. My experience says that on 2 layer boards with short routes to crystal the Cs is typically only 1-2 pF.

We measured such a board with a crystal CL = 12 pF and tried a few capacitor values. Here are the resulting LSE frequency offsets relative to an external precision reference clock:

15 pF: +25 ppm
18 pF: +15 ppm
22 pF: +1,6 ppm

Indirectly it shows that a stray capacitance should be Cs = (2 * 12 pF - 22 pF) / 2 = 1 pF.

lk.dgironi
Associate III
January 17, 2022

Thanks! Indeed I'm using a 2 layer board.

lk.dgironi
Associate III
March 1, 2022

Quick update: design is loaded on PCB, I confirm it's working.