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Jerry Yung
Jerry Yung
Associate III
July 18, 2019
Question

two kinds of deadtime config

  • July 18, 2019
  • 3 replies
  • 1423 views

0690X000009Yr8aQAC.png

yes ， above fig about two kinds of config deadtime ,I don't know how to get that waveform

I have readed RM about deadtime chapter,but I still not clear

This topic has been closed for replies.

3 replies

waclawek.jan
waclawek.jan
Super User
July 18, 2019

You can achieve waveform 1 if you invert OCx, i.e. set the respective TIMx_CCER.CCxP .

Conversely, you achieve waveform 2 if you invert OCxN, i.e. set TIMx_CCER.CCxNP. You may also want to "invert" OCxRef, i.e. use the other PWM mode than used in the first case.

Try and see for yourself.

JW

Jerry Yung
Jerry YungAuthor
Associate III
July 24, 2019

hello , i have some question

I config TIM with " TIM_OCMODE_ACTIVE ", it means when CNT match CCRx, OCxREF is high level. is rise edge ,

  1. disable pro-load feature, when CNT == ARR , next CNT = 0, then corresponding OCxREF high or low ?
  2. when CNT match CCRx, later, if I disable the TIM, OCxREF will keep it's level ? or
  3. and there no way to pull OCxREF level down except for config with " TIM_OCMODE_FORCED_INACTIVE " and " TIM_OCMODE_INACTIVE “ ?
  4. MCU power on default OCxREF high or low ?
  5. for example , I config tim active mode , when ,CNT match ARR ( red arrow point ), I config tim inactive mode , the OCxREF waveform behave like below fig ？

0690X000009Z2JWQA0.png

waclawek.jan
waclawek.jan
Super User
July 24, 2019

I refuse to use Cube or other libraries symbols. Please stick to the terminology used in the Reference Manual.

  1. 2. The Set active on match (OCxM=0b001) mode of output compare sets OCxRef high at the first match (CNT==CCRx) and lefts it so forever, regardless of whether an overflow (CNT==ARR --> 0) or next match occurs.

3. yes; the Force inactive (OCxM=0b100) does that immediately, while Inactive on match (OCxM=0b010) does that later, upon the first match.

4 . good question. I don't know, presumably low.

5 . Sounds so. Try.

JW

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