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patrick_seeboerger
patrick_seeboerger
Associate III
March 10, 2017
Question

Problems leaving ADC_Conv_CpltCallback function

  • March 10, 2017
  • 4 replies
  • 1278 views
Posted on March 10, 2017 at 13:00

Hallo together,

I am using a STM32Nucleo-Board with the STM32F401RE-Controller in combination with the PLC expansion board.

I have used the Cube MX tool to generate the initialization for the peripherie constisting of one ADC Channel PA0 and

one SPI interface.

Now I want to get the ADC value inside the ADC interrupt function, leave the Callback function when I got the actual value and control the digital outputs of the PLC-expansion board via SPI.

My problem is that my program does not leave the callback function and always reads out the ADC.

I tried to use the function  HAL_ADC_Stop_IT(&hadc1) in the Callback function but that did not help to solve the problem.

Can anybody tell me the way to leave the HAL_ADC_ConvCpltCallback function and return back to the code

in the while(1)-function.

You can find my code attached in text-file.

Thank you in advance.

Best regards,

Patrick

    This topic has been closed for replies.

    4 replies

    T J
    T J
    Senior III
    March 11, 2017
    Posted on March 11, 2017 at 02:41

    Hi,

    I had a look, my simple method is a little naughty...

    maybe you can work it a different way.

    in your code:

    /* USER CODE BEGIN 0 */

    void HAL_ADC_ConvCpltCallback(ADC_HandleTypeDef* hadc){

        

            U_ZK = HAL_ADC_GetValue(&hadc1);

             adcUpdated = true;    // added this line to let the foreground know the conversion is completed

            

        }

    char adcUpdated; // added this declaration here to make the Variable visible throughout the code.

    int U_ZK;               // added this declaration here to make the Variable visible throughout the code.

    /* USER CODE END 0 */

    int main(void)

    {

    .

    .

    while(1){

       if(adcUpdated){

             adcUpdated = false;

             printf('ADC value %04x\n\r',U_ZK);

       }

    }

    in my code, I only initialise the interrupt once.

    and I never deinitialise it.

    once the conversion is started the ADC results just get updated in the background

    but I use DMAs, so its slightly different.

    patrick_seeboerger
    patrick_seeboergerAuthor
    Associate III
    March 13, 2017
    Posted on March 13, 2017 at 12:59

    Hi Nick,

    thanks for your reply.

    My problem is that I do not leave the callback-function.

    Concerning to UM1725 Interrupt mode IO operation should work as described below:

    Start the ADC peripheral using HAL_ADC_Start_IT()

    Use HAL_ADC_IRQHandler() called under ADC_IRQHandler() Interrupt subroutine

    At ADC end of conversion HAL_ADC_ConvCpltCallback() function is executed and user can add his own code by customization of function pointer HAL_ADC_ConvCpltCallback

    In case of ADC Error, HAL_ADC_ErrorCallback() function is executed and user can add his own code by customization of function pointer HAL_ADC_ErrorCallback

    Stop the ADC peripheral using HAL_ADC_Stop_IT()

    What kind of microcontroller did you use?

    Maybe it is different to the STM32F401RE...

    Thank you.

    Best regards,

    Patrick

    T J
    T J
    Senior III
    March 13, 2017
    Posted on March 13, 2017 at 13:15

    Yes, I am using the STM32F091

    Are you using uV5 ?

    Did you pay for the license ?

    Not sure how I can pay

    :(

    That’s why I am stuck with the ‘091 today

    I found you have to disable all breakpoints first, then it will single step, then you can insert a breakpoint ok.

    You are a few weeks ahead of me…

    My new terminal board is based on the STM32F767 -208

    I will be initialising the SDRAM hopefully this week.

    ________________

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    image003.jpg : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006Hynr&d=%2Fa%2F0X0000000bCa%2F3P.yqUfoWwWsHsyo_f6gE2OLrJFfHrId5cW67HOu11s&asPdf=false

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