CubeMX STM32L433CC ETR2 Input bug?

Hi

When TIM2 of this device is configured according to the screenshot, the following code will be generated:

void HAL_TIM_Base_MspInit(TIM_HandleTypeDef* tim_baseHandle)
{
 GPIO_InitTypeDef GPIO_InitStruct;
 if(tim_baseHandle->Instance==TIM1)
 {
 /* USER CODE BEGIN TIM1_MspInit 0 */
 /* USER CODE END TIM1_MspInit 0 */
 /* Peripheral clock enable */
 __HAL_RCC_TIM1_CLK_ENABLE();
 /* USER CODE BEGIN TIM1_MspInit 1 */
 /* USER CODE END TIM1_MspInit 1 */
 }
 else if(tim_baseHandle->Instance==TIM2)
 {
 /* USER CODE BEGIN TIM2_MspInit 0 */
 /* USER CODE END TIM2_MspInit 0 */
 /* Peripheral clock enable */
 __HAL_RCC_TIM2_CLK_ENABLE();
 
 /**TIM2 GPIO Configuration 
 PA0 ------> TIM2_ETR 
 */
 GPIO_InitStruct.Pin = GPIO_PIN_0;
 GPIO_InitStruct.Mode = GPIO_MODE_AF_PP;
 GPIO_InitStruct.Pull = GPIO_NOPULL;
 GPIO_InitStruct.Speed = GPIO_SPEED_FREQ_LOW;
 // This line is missing:
 GPIO_InitStruct.Alternate = GPIO_AF14_TIM2;
 HAL_GPIO_Init(GPIOA, &GPIO_InitStruct);
 /* USER CODE BEGIN TIM2_MspInit 1 */
 /* USER CODE END TIM2_MspInit 1 */
 }
}
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The line marked as missing becomes not generated leaving the pin as output.

Besides this error the wording within the Configuration of TIM2 -> GPIO is also missleading, telling the user

that this is an output pin. 'Maximum Output Speed: ...'

CubeMX 4.19

STM32Cube_FW_L4_V1.6.0.

Dieter