Associate III

Question

STM32F103RB CAN J1939 identifier

Posted on June 19, 2017 at 13:45

Hi evryone, I'm using STM32f103rb card to communicate with another STM32f103rb thanks to STM32F103Rb CAN protocole, and I'm looking for using J1939.

I have parameter my identifier like that :

hcan.pTxMsg->StdId = 0x01;

hcan.pTxMsg->ExtId = 0x01DAD4DC1;

hcan.pTxMsg->RTR = CAN_RTR_DATA;

hcan.pTxMsg->IDE = CAN_ID_EXT;

hcan.pTxMsg->DLC = 8;

and I'm trying to configurate my filter, but I've no idea of what could be the following configurations :

sFilterConfig.FilterIdHigh

sFilterConfig.FilterIdLow

sFilterConfig.FilterMaskIdHigh

sFilterConfig.FilterMaskIdLow

sFilterConfig.BankNumber

Anyone can help me ?

Thanks for your attention,

Regards,

Nicolas.

This topic has been closed for replies.

Guru

Posted on June 19, 2017 at 14:44

https://community.st.com/0D50X00009XkYJGSA3

You have to construct the mask and id so the comparator in the peripheral can recognize the specific bit pattern

The mask is ANDed with the bit stream and the ID is then compared.

The EXID complicates the construction of the bit patterns, but look at the diagram of what the chip is looking for.

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Guru

Posted on June 19, 2017 at 18:37

HCANFilter_Struct.FilterIdHigh = (EXTID >> 13) & 0xFFFF; // 29-bit EXTID

HCANFilter_Struct.FilterIdLow = ((EXTID << 3) & 0xFFF8) | 4;

HCANFilter_Struct.FilterMaskIdHigh = 0xFFFF; // MSB

HCANFilter_Struct.FilterMaskIdLow = 0xFFFC; //LSB

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Associate III

Posted on June 21, 2017 at 10:36

thank you so much, but I need to know how you have doing this

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