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CRedd.2
CRedd.2
Associate
Nov 18, 2021 6:41 PM UTC
Solved

What is the P_CURRENT in STDES-EVT001V1 design, please help me out to know what exactly it is ?

0693W00000GY5MsQAL.png

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Peter BENSCH
Peter BENSCHBest answer
ST Technical Moderator
Nov 19, 2021 1:12 PM UTC

Very well spotted!

However, this is the 2nd capacitor bank (C21-22, C25..28, C30-31) with a total capacity of 1320µF directly buffering spike currents. They are therefore directly connected between the drain of the high-side FET and the source of the low-side FET.

The main capacitor bank (C17-20, C23-C24) between VBUS and GND provides a total capacity of 2820µF.

The single-shunt is located between the negative pole of the main capacitor bank and the negative pole of the 2nd capacitor bank you mentioned, which can also be seen in the layout using a GERBER viewer.

Regards

/Peter

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6 replies

Peter BENSCH
Peter BENSCH
ST Technical Moderator
Nov 19, 2021 12:15 PM UTC

Welcome, @CRedd.2​, to the community!

this topic does not belong to eDesignSuite, so I moved it to Motor Control Hardware.

Regarding your question: P_CURRENT is the phase current, a net that connects to all three phases in STDES-EVT001V1 and is routed via R22, R23, R105 and R106 to ground (single-shunt control).

If the problem is resolved, please mark this topic as answered by selecting Select as best. This will help other users find that answer faster.

/Peter

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CRedd.2
CRedd.2Author
Associate
Nov 19, 2021 12:34 PM UTC

Hello,

still i am not clear with this answer, why because as per schematics my assumption is P_Current is ground is this correct or not...VBUS(+) is supply and P_Current is Ground(-)?

Peter BENSCH
Peter BENSCH
ST Technical Moderator
Nov 19, 2021 12:40 PM UTC

No, all tracks with P_CURRENT are connected.

Then P_CURRENT is connected to the single-shunt resistors mentioned before, consisting of four resistors in parallel.

Finally these shunt resistors are then connected to GND.

So all three phase currents flow through the single-shunt resistor to GND and can be measured jointly by the comparator in U2.

Regards

/Peter

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CRedd.2
CRedd.2Author
Associate
Nov 19, 2021 1:38 PM UTC

Brave sir, i'm clear now.

If any i will be back with questions.

Thank You so much sir!!!!

Kindly, please support as usual.

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