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Associate
Oct 19, 2026 3:23 PM UTC
Solved

LDQ40PUR Adjustable Output Setting

I am evaluating the LDQ40PUR (adjustable version) and there is some ambiguity in the datasheet for setting the output voltage.

The datasheet states:

The resistor divider should be selected as follows: VOUT = (1+R1/R2)*VADJ, considering IADJ negligible.

 

What is VADJ? Should this be VREF (1.2V)?

 

I assumed VADJ = VREF = 1.2V, and calculated my output with the following values:

R1 = 340kOhm

R2 = 102kOhm

VOUT = (1+340k/102k)*1.2V = 5V

 

However, when I built the circuit with these values, I am not getting this value at the VOUT pin.

 

When VIN is 3.6V or higher, I get VOUT = VIN (e.g. VIN=7V, VOUT=7V)

 

Here is the schematic for my circuit:

Schematic for LDQ40PUR test circuit

 

Peter BENSCH
Peter BENSCHBest answer
ST Technical Moderator
Oct 20, 2026 2:42 PM UTC

​@JoshuaT Something seems to be wrong with your setup and/or measurements: even if the 7V reach the output unchanged (as ​@TDK says, the cause must be found), then the divided voltage should be present at pin 5, i.e. 102*7V/(102+340) ~ 1.62V.

 

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6 replies

Peter BENSCH
ST Technical Moderator
Oct 19, 2026 7:47 PM UTC

Welcome ​@JoshuaT, to the community!

Your schematic is correct; with 340k+102k, your output voltage should be 5.2V when the input is 5.7V. In the worst-case scenario at 250mA, there could be a drop-out of up to 1V, meaning 6.2V would be required.

Are you sure you haven’t accidentally soldered the device on rotated by 180°?
What voltage do you measure at pin 5 when there is 7V at the input?

Regards
/Peter

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JoshuaTAuthor
Associate
Oct 19, 2026 8:05 PM UTC

Hi,

There are some mistakes in my math in my post, I am actually targeting 5.2V as you deduced.

 

With 7V at pin 1, I see 3.87V on pin 5. 

I have it soldered as follows:

Is this the correct orientation?

TDK
Oct 19, 2026 9:06 PM UTC

If you’re getting the same output voltage as input voltage, there is a short somewhere and/or it’s being backpowered. At a minimum, you should see a different between them of the dropout voltage. Perhaps you could measure them more precisely.

Is there any load on the output? Consider setting a load of at least 10 mA or so.

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Peter BENSCH
Peter BENSCHBest answer
ST Technical Moderator
Oct 20, 2026 2:42 PM UTC

​@JoshuaT Something seems to be wrong with your setup and/or measurements: even if the 7V reach the output unchanged (as ​@TDK says, the cause must be found), then the divided voltage should be present at pin 5, i.e. 102*7V/(102+340) ~ 1.62V.

 

In order to give better visibility on the answered topics, please click on Accept as Solution on the reply which solved your issue or answered your question.
JoshuaTAuthor
Associate
Oct 20, 2026 4:05 PM UTC

Hi Peter,

 

The part must have been either damaged or not soldered properly. I guess I am not able to evaluate it in the DFN package.

 

Do you know if there is any availability for this part in the SOT23 package in quantities less than 3000?

Peter BENSCH
ST Technical Moderator
Oct 20, 2026 9:02 PM UTC

Well, in theory, the DFN6 (2x2) should be possible to solder by hand, but it requires an exceptionally steady hand, as well as plenty of experience in handling such packages with a 0.65 mm pitch.

The automotive variant, the LDQ40MRY in an SOT23-5L package, is indeed available in the eStore in quantities of 500; however, this is not a technical issue that should be discussed within the community, but rather a temporary availability issue that must always be clarified with the relevant distributor.

Good luck!

Regards
/Peter

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