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M24C04-F DNF5 I2C address
Dear All,
can someone, please, specify the meaning of the bit 1 as 'A8' in the I2C address of the M24C04-FMH6TG?
I can't find any explanation of this value.
Thank you
Peter BENSCHBest answer
ST Technical Moderator
September 29, 2025
The M24C04 contains 512 (2^9) bytes, which require 9 bits for addressing. Since an address byte only has 8 bits (A0...A7), the 9th bit (A8) must also be transferred, for which bit b1 in the device select code is used.
Does it answer your question?
Regards
/Peter
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