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dcramer
Associate II
June 3, 2008
Question

Interrupts while booting from bank 1

  • June 3, 2008
  • 6 replies
  • 1292 views
Posted on June 03, 2008 at 18:27

Interrupts while booting from bank 1

This topic has been closed for replies.

6 replies

dcramer
dcramerAuthor
Associate II
May 17, 2011
Posted on May 17, 2011 at 09:53

Ok. Do I add this code before I jump to bank 0? My code is linked to start at 0x80000, so should I make the asm (''MOV R1,#0x10000'');

read asm (''MOV R1,#0x80000''); instead.

rgreenthal
Associate III
May 17, 2011
Posted on May 17, 2011 at 09:53

Try this to switch to b0s1

__ramfunc void SwitchToRun (void)

{

SCU->CLKCNTR = 0x00020002;

SCU->GPIOOUT[0] = 0x00000000;

SCU->GPIOOUT[1] = 0x00000000;

SCU->GPIOOUT[2] = 0x00000000;

SCU->GPIOOUT[3] = 0x00000000;

SCU->GPIOOUT[4] = 0x00000000;

SCU->GPIOOUT[5] = 0x00000000;

SCU->GPIOOUT[6] = 0x00000000;

SCU->GPIOOUT[7] = 0x00000000;

SCU->GPIOIN[0] = 0x00000000;

SCU->GPIOIN[1] = 0x00000000;

SCU->GPIOIN[2] = 0x00000000;

SCU->GPIOIN[3] = 0x00000000;

SCU->GPIOIN[4] = 0x00000000;

SCU->GPIOIN[5] = 0x00000000;

SCU->GPIOIN[6] = 0x00000000;

SCU->GPIOIN[7] = 0x00000000;

SCU->PRR0 = 0x00001053;

SCU->PRR1 = 0x00000000;

SCU->PCGRO = 0x000000DB;

SCU->PCGR1 = 0x00000000;

asm (''MOV R1,#0x10000'');

asm (''MOV PC,R1'');

}

dcramer
dcramerAuthor
Associate II
May 17, 2011
Posted on May 17, 2011 at 09:53

I implemented a boot loader that runs in bank 1 according to the sample code in an2675.zip. I can start the application in bank 0, but I can not get any interrupts working. This code was working until I implemented the coding changes recommended in the errata for flash memory remapping, in order to solve the external reset issue. I am having no problem getting the code to start, but I can not get any interrupts to occur.

Thanks

dcramer
dcramerAuthor
Associate II
May 17, 2011
Posted on May 17, 2011 at 09:53

That suggestion didn't work. It looked good though.

dcramer
dcramerAuthor
Associate II
May 17, 2011
Posted on May 17, 2011 at 09:53

Yep. 512 K address. Will try it in the morning and let you know.

Thanks

rgreenthal
Associate III
May 17, 2011
Posted on May 17, 2011 at 09:53

Looks good to me, if you are jumping to 512K address