ISM330DLC Application note AN5125 Rev 2 p29 section 4.5.2 examples of output data - specifically table 23 line 2 starting 350mg - How did you work out 16h and 69h? Can you please supply more detail - I do not understand how you got the numbers you di

Thank you!

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Best answer by Eleon BORLINI

Hi @CHarr.1 , taking your example:

you have to concatenate OUTX_H_XL (29h), OUTX_L_XL (29h) obtaining 1669h.

From the datasheet p.8, you know that the acceleration sensitivity is 0.061mg/LSB, when FS is +-2g.

If you convert the concatenated register data in two's complement as required by the datasheet, you get decimal 5737.

Multiply it times 0.061mg/LSB and you will get 349.957 mg.

Regards

ST Employee

Hi @CHarr.1 , taking your example:

you have to concatenate OUTX_H_XL (29h), OUTX_L_XL (29h) obtaining 1669h.

From the datasheet p.8, you know that the acceleration sensitivity is 0.061mg/LSB, when FS is +-2g.

If you convert the concatenated register data in two's complement as required by the datasheet, you get decimal 5737.

Multiply it times 0.061mg/LSB and you will get 349.957 mg.

Regards

Associate II

Excellent - thank you!

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