maybe, only because the 2nS is not enough time to overheat anything.
You could divert that energy by using a schottky diode from ground on that pin, clamping to -0.4v max
This depends on the actual circuitry "behind the pin", I would be cautious.
MOSFETs, for example, have a dV/dt limit. Exceeding that limit will kill it, without much energy involved (relative to it's total admissible power dissipation). I've seen FETs dying that way.
Hello Tomas Bengtsson ,
For the Input voltage on FT pins: VSS − 0.3V ; with maximum: VDD+4.0V
For more details, please check the related datasheet , in the Table 15. Voltage characteristics
Noted that VIN maximum value must always be respected. You should refer to Table 16 for the values of the maximum allowed injected current.
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