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Interrupt do not run when resume Swing Thread

Question asked by Suyog Buradkar on Oct 30, 2017

Hello ST Community,

 

 

I have three Threads Running in y code in main function I am declaring 3 Threads and suspend Two of them. My Interrupt Routine calls a function which after words resumes the one Task named "Swing". But While this task is running whenever interrupt occurs it does not run at all. 

 

 

 

 

int main(void)
{

 


HAL_Init();


SystemClock_Config();

 


MX_GPIO_Init();
MX_TIM3_Init();
MX_TIM4_Init();
MX_USART1_UART_Init();
MX_USART2_UART_Init();
MX_I2C2_Init();

/* USER CODE BEGIN 2 */
HAL_UART_Receive_IT(&huart2,(uint8_t *)Rx_Data,1);
HAL_TIM_IC_Start_IT(&htim3,TIM_CHANNEL_2);
HAL_TIM_IC_Start_IT(&htim4,TIM_CHANNEL_1);

 

/* Create the thread(s) */
/* definition and creation of defaultTask */
osThreadDef(defaultTask, StartDefaultTask, osPriorityNormal, 0, 128);
defaultTaskHandle = osThreadCreate(osThread(defaultTask), NULL);

 

/* USER CODE BEGIN RTOS_THREADS */
/* add threads, ... */
osThreadDef(SwingTask, Swing, osPriorityNormal, 0, 128);
SwingTaskHandle = osThreadCreate(osThread(SwingTask), NULL);

osThreadDef(Task1, Task1, osPriorityNormal, 0, 100);
osThreadCreate(osThread(Task1), NULL);
vTaskSuspend(defaultTaskHandle);
vTaskSuspend(SwingTaskHandle);

vTaskStartScheduler();
/* Start scheduler */
osKernelStart();

/* We should never get here as control is now taken by the scheduler */

/* Infinite loop */
/* USER CODE BEGIN WHILE */
while (1)
{
/* USER CODE END WHILE */

/* USER CODE BEGIN 3 */

}
/* USER CODE END 3 */

}

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